Quant Question Of The Day: 154
How many triplets of non-negative integers (x,y,z) satisfying the equation xyz + xy + yz + zx + x + y + z = 2014
1. 18
2. 24
3. 27
4. 36
5. None of the above
xyz + xy + yz + zx + x + y + z = 2014 xyz + xy + yz + zx + x + y + z + 1 = 2015 ( x+1) ( y+1) ( z+1) = 2015 = 5 × 13 × 31 If all (x, y , z ) are positive then there are 3! = 6 solution If exactly one of x, y and z is 0, there are 3 18 solutions. If exactly two of x, y and z zero then there are 3 solutions. Total: – 6 + 18 + 3 =27 solutions.
See our previous ‘Questions of the Day’:
Quant Question Of The Day: 153
Quant Question Of The Day: 152
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