Quant Question Of The Day: 21
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Geometry
In the diagram which is not drawn to scale , the circles are tangent at A , the center of the larger circle is at B , CD = 12 , and EF = 8. What is the radius of the smaller circle ?
Let the larger radius be x. By the power of a point theorem,
AB × BC = FB2
x (x-12) = (x-8)2
4x = 64,
x = 16.
Now the smaller radius is AC/2 = (AB+BC)/2 = (2x -12)/2 = x-6 = 10. Hence the radius of the smaller circle = 10.
Solve our previous ‘questions of the day’
1.Quant Question Of The Day: 20
2. Quant Question Of The Day: 19
6.68
10
Correct!
10
Well done Aaradhya ! 10 is Correct!
Try today’s Question : http://tathagat.mba/quant-question-of-the-day-22/
R=16
r=10
Perfect Abhishek !
Try today’s Question : http://tathagat.mba/quant-question-of-the-day-22/
Please post the solution for this.
use secant theorem.
BF*BE=BC*BD
Hi ! Shubhra
Check the solution Here : http://tathagat.mba/quant-question-of-the-day-22/