Quant Question Of The Day: 23
[latexpage]
Geometry
ABCDEF is an equiangular hexagon ( each of its interior angle is 120°) . Find the EF + FA, if AB = 2, BC = 4, CD = 3 and DE = 5.
A. 4
B. 5
C. 6
D. 7
E. None of these
Draw ABCDEF as per given conditions. Now extend AB, CD and EF on both sides so that PQR is an equilateral triangle.
Because ∠ABC = 120°, so ∠CBR = 60°, similarly ∠BCR = 60°. Thus ∠R = 60°.
Similarly ∠P = ∠Q = 60°.
So PR = 5 + 3 + 4 = 12, and PQ = 5 + EF + FA = 12.
Hence EF + FA = 12 – 5 = 7.
Solve our previous ‘questions of the day’
Quant Question Of The Day: 22
Quant Question Of The Day: 21
A.
Hi Shivam
7 is the correct answer . Check the solution here : http://tathagat.mba/quant-question-of-the-day-23/
Do try today’s question : http://tathagat.mba/quant-question-of-the-day-24/
None of the above
Hello Aaradhya!
Option D is correct . Check the solution here : http://tathagat.mba/quant-question-of-the-day-23/
Do try today’s question : http://tathagat.mba/quant-question-of-the-day-24/