Quant Question Of The Day: 59
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Algebra
Both roots of the polynomial x2 – bx + 1 are integers. And further one root is cube of the other. Which of the following is not a possible value of b?
A. -2
B. -1
C. 2
D. All are possible
Just check the options, for b = -2, polynomial becomes (x + 1)2 and both roots are integers and satisfy other condition also.
For b = 2, polynomial becomes (x – 1)2 and both roots are integers and satisfy other condition also.
But for b = -1, polynomial becomes x2 + x + 1 and roots are non-real. Thus b cannot be equal to -1
See our previous ‘Questions of the Day’:
D.
all of the above
D.
B
B
B