Quant Question Of The Day: 66
[latexpage]
Counting
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions ?
A. 16
B. 36
C. 60
D. 180
Since 3, 3, 5, 5 , i.e odd digits occupy even positions 2,4,6,8 and 2,2,8,8,8, occupy remaining 5 odd places .
So, required number of ways = 4!/(2!×2!) × 5!/(2!×3!) = 60
See our previous ‘Questions of the Day’:
Quant Question Of The Day: 65
Quant Question Of The Day: 64
C.60
(5!/3! 2!) * (4!/2! 2!)
36.
4+2^5
60
60
C.60
5!/2!2! * 4!/2!3!