Quant Question Of The Day: 75
Counting
Find the number of ways in which 5 members can be selected from three teams (each having three members) such one member is selected from each team.
There are two possible cases :
(i) (1,1,3) : 3C1 ×3C1×3C3 × 3!/2! =27
(ii)(1,2,2) : 3C1×3C2×3C2×3!/2! =81 total=27+81=108
108
162
162
108