Quant Question Of The Day: 79
Geometry
In the figure A is the centre of the circle . B is a point on the circumference and AFBE is a rectangle . AE and AF produced meet the circle at D and C respectively . If EF = 10 and ED = 2 . Find FC .
AB = EF = AD = 10 ( radii)
AE = 10 – 2 = 8
Applying Pythagoras Theorem, BE = 6 = AF
Hence , FC = 10 – 6 = 4
4
4