There are 10 consecutive natural numbers. Average of this numbers is k. If 4 more numbers consecutive numbers to the smallest of the 10 numbers are added to set, then what will be new average.

  1. k+1
  2. k-4
  3. k-2
  4. can’t be deteremined

Solution for Quant Question of the day: 260

By Allegation

32                       53

            35

18          :        3

hence quantities should be mixes in 6:1

so 49 litres should have 42 litres of 32% and 7 litres of 53%.

hence 7 litres quantity should be replaced.

See our previous quant question of the day:

Quant Question Of The Day: 260

Belgian shake company made Chocolate shake by mixing chocolate and milk. The 49 litres container is filled with 32% chocolate and shipped to South campus. But in the study it was found that students in the south campus demand more chocolate concentration in the shake. So Belgian shake company decided to make it 35% concentration of the chocolate. How much quantity must be replaced with 53% chocolate shake to achieve 35% concentration.

  1. 14 liters
  2. 7 litres
  3. 21 litres
  4. 5 litres

Solution for Quant Question of the day: 259

(1) There are multiple values of a for hcf (a,b ) = 8 (8,16; 16,24)

(2) There are multiple values of a for lcm (a,b) = 48 (eg 8,48; 16, 48)

combines – there are still multiple values of a  (eg, 8,48 ; 16,24)

See our previous quant question of the day:

Quant Question Of The Day: 259

Following Question is followed by 2 statements. 

Mark (1), if question can be answered using one of the statements but not the other

Mark(2), if question can be answered using either of the statements.

Mark(3), if question can be answered using both the statements together but not by only one of those. 

Mark(4), if question cannot be answered using both the statements together.

What is the Value of integer A?

I HCF(A,B) = 8

II LCM(A, B) =48

Solution for Quant Question of the day: 258

let’s say he pays Rs100 for 100 gms

so he buys 130gms instead of 100gms (in Rs. 100)

and sells 70gms instead of 100gms (in Rs. 100)

now 60 gms is his profit over qty sold {70 gms in 100 rs, So further 60 gms in 7/6*100 rs)

60/70*100 = 85.71% profit

See our previous quant question of the day:

Quant Question Of The Day: 258

If a merchant gives cheats 30% while buying and cheats 30% while selling. Find his profit percentage

  1. 60% profit
  2. 85.71% profit
  3. no profit no loss
  4. 30% profit

Solution for Quant Question of the day: 257

using alligation

40% grads                                70% non grads

                   60% boys        

10                             :                   20

hence ration of grads to non grads is 10:20 = 1:2

hence % of grads = (grads/total)*100 = 1/3*100 = 33.33%

See our previous Quant Question of the day:

Quant Question Of The Day: 257

In a group of boys and girls, some people are graduates and other are not. 40% of graduates and 70% of non-graduate are boys. If there are total 40% girls in the group then what is the percent of graduates in the group.

  1. 33.33%
  2. 66.66%
  3. 50%
  4. 55.5%

Solution for Quant Question of the day: 256

They meet after 6 days (lcm of 2 and 3) or after 6n days

and Wednesday will come after 3 days or 7k+3 days

so 7k+3 = 6n (where k and n are integers)

k = 3 , then, n =4

hence they will meet after 7(3)+3 = 24 days for first time on a wednesday

and then after 42 days (lcm of 6 and 7), they will again meet (for 2nd time) on a Wednesday. It means after 66 days Viraj will  have 2 crystals.

See our Previous Quant Question of the day

Quant Question Of The Day: 256

Arohi and Viraj visit the Museum every 2 and 3 day, they met in the Museum on a 10th Feb and it was Sunday. Every time they meet on a Wednesday Arohi gives Viraj a Crystal. When will Viraj Get 2nd Crystal from Arohi, If he hadn’t receives any crytal till 10th Feb.

  1. After 24 days
  2. After 42 days
  3. After 66 days
  4. After 90 days

Solution for Quant Question of the day: 255

We will take 3 smallest prime numbers to start that are 2,3,5

now we will pick 2 at a time from the above list and multiply them. It will be 3C2 ways = 3 ways

2*3    3*5     2*5

Now these 3 numbers are not co-prime and also none of them is multiple of other.

Hence 3 smallest prime will satisfy the requirement.

And Since these are the only prime in the list of numbers, hence their LCM will be 2*3*5 = 30

See Previous Quant Question of the day:

Quant Question Of The Day: 255

If Z is a set of 3 numbers, which are not co-prime to each other and none of them is multiple of other, then what is the minimum LCM of these 3 numbers

  1. 60
  2. 8
  3. 24
  4. 30

Solution for Quant Question of the day: 254

a/(a+b) = b/(a-b)

Let’s divide the entire equation by ‘b’ (let’s say a/b = k)

so k/(k+1) = 1/(k-1)

k(k-1) = (k+1)

k^2-k = k+1

k^2-2k = 1

k^2-2k+1 = 2

(k-1)^2 = 2

k-1 = (2)^0.5

k =1.41+1 = 2.41

hence a/b = 2.41 , so ‘a’ is 241% of ‘b’

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Quant Question Of The Day: 254

‘x’ as percentage of ‘(x+y)’is same as ‘y’ as percentage of ‘(x-y)’. Then ‘x’ is what percentage of ‘y’. 

  1. 100%
  2. 241%
  3. 50%
  4. 141%

Solution for Quant question of the day: 253

400 = 2^4 * 5^2

a and b are two numbers that give lcm 400. 

One of them have 2^4 and others has any power of 2 upto 4

0 4, 1 4, 2 4, 3 4, 4 0, 4 1, 4 2, 4 3, 4 4
which is 9 pairs

Same way one of them have 5^2 and other has any power of 5 upto 5

0 2, 1 2, 2 0, 2 1, 2 2
which is 5 pairs

hence total 9*5 = 45 ordered pairs

but we don’t want ordered pairs, hence 23 pairs.

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Quant Question Of The Day: 253