A sum becomes 4 times of itself in 8 years at compound interest. In how many years it becomes 8 times of itself at same rate of compound interest?
Answer: (2) 12 years Solution: p(x)^8 = 4p (x = (1+r)) x^8 = 4 x^4 = 2…..(1) now px^(n) = 8p x^(n) = 8 from (1), 2 = x^4 so 8 = x^12 hence value of n = 12 years
A horse can carry maximum 400 carrots on his back. Owner of the horse has 1200 carrots. He has to transport them at a destination 400 miles away using his horse, But horse eats one carrot to move 1 mile. What is the maximum carrots he can transport to the destination.
Solution: This is based on utilization of maximum efficiency point where 800 carrots can be transported using 2.5 return trips, means in 5 one side trips. To reach to this point horse will eat 400 carrots in 5 triops. means this point is 80 miles away. Now the remaining distance is 320 miles Next the point where 400 carrots can be transported in 1.5 round trips or 3 one side trips. horse will eat 400 carrots to get there in 3 trips, means 133 miles away. now the remaining distance is 320-133= 187 miles and carrots are 401 left. so now horse will further eat 187 carrots. So the maximum carrots transported will be 401-187 = 214 carrots
If there are 10 balls each of Red, blue and green color in a box, then what is the minimum number of balls that should be taken out of the box to ensure that 3 of them are of same color
Answer: (3) 7 Solution: in the worst case scenario when 6 balls are taken out , there will b 2 red balls, 2 blue balls and 2 green balls. Them moment 7th ball is picked up, it will be one of the 3 colored balls. Hence now in there will 3 same colored balls.
A sum was lent for an year and another was lent for 2 years at 12% interest rate. Each sum amounted to the same value. The ratio of first sum to second sum is?
Answer: (1) 28:25 Solution: a(1+r%)^1 = b(1+r%)^2 a/b = 1+r% = 1+12/100 = 28/25
if p men take q hours to dig 3*3*4 well. Then how many days ‘r’ men will take to dig 8*3*5 well.
Anwer: 10pq/3r hours Solution: 3*3*4 well is work done in p*q man hours 8*3*5 well is work done in pq(8*3*5)/(3*3*4) = 10pq/3 man hours now work = 10pq/3 = r*x manhousrs x = 10pq/3r hours
If 8 men and 10 women take 3 and 4 days respectively to dig a 4*4*4 pit. How many days 6 men and 15 women combined will take to dig the same pit?
Answer: (2) 1.6 days Solution work = 8*3 mandays = 10*4 = womandays from above equation 6 mandays = 10 womandays so now 6 men+ 15 women = 25 women let’s say 25 women take x days 25x = 10*4 x = 1.6 days
If DERANGES is coded 45915751, then how VARIETY will be coded in that code
Answer: (4) 4199527 Solution: Every letter is coded as the digital sum of its position. for example R is 18th position. digital sum is 9.
For how many values of n 36/(n+5) is also an integer?
18
9
8
infinite many
Answer: (1) 18 Solution 36/(n+5) will be integer, when (n+5) is factor of 36 taking both positive and negative value there are 9 positive and 9 negative factors of 36, hence total 18 solutions.
