Hello sir,
Please help me with the approach.
Hello Abhi !
Alternate Approach :
please share the solution to this problem
Hi Richa!
PFA the solution .
Ohh thank you. The question says to find the length of tangent from the center of one circle to the other, I thought it meant from one center to the other center. The question wasn't clear to me.
Hello Sir, please help me with the below 2 questions:
Q1) Two circles of radii 14 and 22 units are 45 units apart at the centers. What is the length of their common internal tangent?
Q2) A square whose area is 64 is partitioned into four congruent smaller squares. Find the circumference of the circle that passes through the centers of the four subsquares.
Q. 1
Q . 2
Hey sir, please help me with the below question.
Hello Richa !
PFA the approch.
Sir, how do we know that angle CAB is 60°?
Or if I put it in different term- how do we know that triangle ABC is an equilateral triangle?
Please help.
AC and AB are circular arcs so
AC = AB = BC = r ( Radii )
Hence , ABC is an equilateral triangle .
Hi sir, please help.
Hello Aniket ,
PFA the attached solution .
In the rectangle ABCD , the perpendicular bisector of AC divides the longer side AB in a ratio 2:1 . Then the angle between AC and BD is?
Sir the figure is troubling me
Hello Richa
PFA the solution.
An easier approch :
Hi sir, please share the solution
Hello Richa ,
All the options seem wrong the correct answer is 10 - 2sqrt{15}
Hi sir, please help with this problem
Join E - A and D - A
the angle formed ( EAD ) will be 30º
So the angle formed by the side of the square at center = 60º
Hence, Equilateral triangle
Radius = Side of the square = 2
Sir, can you help me with the diagram of this question? I'm not able to visualize or draw the diagram.
AB and CD are perpendicular to a diameters of Circle O. Let CM be a chord that intersect AB at E, so that CE=6 and EM =5. Find the circumference of the circle.
This problem is similar to the question of the day : 25
http://tathagat.mba/quant-question-of-the-day-25/ :
Hello Richa PFA the approch .
PFA the solution
