India is a multi-religion, multi-language and multi-cultural country

where people belonging to different religions join in celebrating

the festivities together. The Indian Government declares such big

occasions as public holidays to enable the citizens to enjoy and

foster the feelings of brotherhood.Five broad-minded persons

belonging to different religions were asked to give their preferences

of four such festivals which they would like to enjoy with likeminded

brethren. Their options are

A. Holi, Dussehra, Diwali, Guru Nanak Birthday

B. Shivratri, Christmas, Onam, Eid

C. Holi, Shivratri, Christmas, Diwali

D. Holi, Dussehra, Guru Nanak Birthday, Eid

E. Christmas, Diwali, Onam, Guru Nanak Birthday

67. Which pair celebrates Christmas and Onam but not Dussehra

and Holi?

(a) A and C (b) A and E

(c) B and D (d) B and E

68. Which pair does not participate in Eid and Onam but joins in

Holi?

(a) A and B (b) A and C

(c) C and D (d) D and E

69. Who enjoys Holi and Eid but not Diwali and Christmas?

(a) B (b) C

(c) D (d) E

70. Which of the following expressions will be true if the

expression R > O = A > S < T as definitely true?

(a) O > T (b) S < R

(c) T < A (d) S = O

Hello Apoorva!

From the first statement :

B < C , D < A , C < E

From the second statement :

A > F , A > G , F > D

and G > F .

now , G was as old as B when A was as old as G .

Hence , A = B .

Combining the results we get : E > C > B = A > G > F > D .

10. (B) E

11. (B) D

12. (C) A and B

13. (C)

Let cheque amount be Rs X and Y paise.

The confused bank teller cashed Rs Y and X paise.

It is given that after buying a toffee for 50 paise, Shailaja is left with 3 times of the amount on the cheque.

Therefore, 3(X + Y/100) = (Y + X/100 – 50/100)

(299X + 50)/100 = (97Y/100)

Y = 3X + (8X + 50)/97

X = 18 gives an integral value of Y.

Hence Option (D)

P=pakistan

C=chinese

I=indian

C P P I C I P C

Q R P S/T W S/T

we are left with U and V which will occupy C place hence option A

To find minimum number of students who attended admission process of IIMA , which is the maximum ( IIMA > IIMB > IIMC ) , assign minimum values for those who attended admission process of all the three IIMs and those who attended exactly two and distribute the remaining equally :

Minimum: 40 + 2 + 3 = 43

Please solve this

Correct answer combinations can be 5,4,3,2,1

or 5,3,2,1,0

when we check through 5,4,3,2,1..Then there should be atleast 2 people with 4 same answers. But there are no such 2 people

Hence correct answer combination will be 5 ,3 ,2 ,1, 0

now there there are 3 matches for nobita and shizuka, hence one of them answered 4 correctly.

Further we check then there is only one person who has 2 matches with shizuka and there is no such person for nobita, hence shizuka answered 4 of them correctly.

Now with shizuka's answer we can answer all other questions