Percentage

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# Percentage

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During an election 70% of the people who polled said that they would vote for Mr. X Of those who said that, only 60% actually voted for X. Out of those who did not say they would vote for Mr. X, 70% actually voted for X. What percent of those who polled did vote for X?

• a.66%
• b.42%
• c.74%
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So Sir what can we say about the applicability of this rule . Can it be applied to all such compound interest questions ?

Yes!

But, it is an approximate value and its accuracy reduces as the interest rate becomes high.

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Of the ones who said they shall vote for X--->70% of 60 % of people = 42% of people actually voted for X

Of the ones who did not say they'll vote for X--->70% of 30 % of people = 21% of people actually voted for X

Vot for x = 42% + 21% =63%

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Hello sir,

Ravi invests 50% of his monthly savings in fixed deposits. Thirty percent of the rest of his savings is invested in stocks and the rest goes into Ravi's savings bank account. If the total amount deposited by him in the bank (for saving account and fixed deposits) is Rs 59500, then Ravi's total monthly savings (in Rs) is

Hello Kinsuk,

Let Ravi's total saving is Rs 100

Investment in fixed deposit = Rs 50

Remaining = Rs 50

Investment in stock = 30% of 50 =Rs 15

Remaining = 50 - 15 = Rs 35

Investment in saving account = Rs 35

If the total amount deposited by him in the bank (for saving account and fixed deposits) is Rs 85, then his total monthly saving is Rs 100.

So, when the total amount deposited by him in the bank (for saving account and fixed deposits) is Rs 59500, then his total monthly saving = (59500 x 100)/85 = Rs 70000

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Hello sir,

this question was asked in CAT 2017, please explain the solution in detail.

If a seller gives a discount of 15% on retail price, she still makes a profit of 2%. Which of the following ensures that she makes a
profit of 20%?
A) Give a discount of 5% on retail price B) Give a discount of 2% on retail price C) Increase the retail price by 2%
D) Sell at retail price

Hello S.Nath,

Find the solution below,

Let the retail price be 100.

Discount = 15

Selling price = 85

Cost price = (85/1.02) =(500/6)

In order to make a profit of 20%, the selling price =(500 x 1.20)/6 = 100

The seller must sell at the retail price

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A rober entered in a class room.He thefts 80% prncils,85% pens,75%scales and 68% rubbers.Find the minimum percentage of people who lost four items?

all tg members, plz give a try and xplain the funda which should be applied

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Assuming every student of class possesses the equal number of pencils, pens, scales, and rubbers.
Then minimum percentage of people who lost four items = (80 + 85 + 75 + 68) - (3*100) = 308 - 300 = 8%.

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10% of Mexico population migrated to South Asia 10%of the remaining migrated to America and 10% of the rest to Australia. If the female population which was left in Mexico remained only 364500 find the population of Mexico city before the migration and its effect if it is given that before the migration the female population was half the male population and this ratio did not change after the migration ?
can anyone provide me the solution of it in easy way

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Let the population of Mexico be x
Population after 10% migrated to SA = 0.9x
Population after 10% migrated to America = 0.9x * 0.9 = 0.81x
Population after 10% of the rest migrated to Australia = 0.81x * 0.9 = 0.729x
Let the no of males be a and females be b
=> a+b = 0.729x
Given that b=a/2
and b = 364500
=> a = 2*364500 = 729000
=> 729000 + 364500 = 0.729x
=> x = 1500000

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Ashok sells his goods 50% dearer than shankar and 20% dearer than bishnu. How  much % is bishnu goors dearer than shankar?

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1. In a physical measurements., by mistake S gave his height as 25% morr than normal. In the interviewpanel, he clarified his height is 5 feet 5 inches. Find the % correction made by candidate from hisbstated height to his actual height

If the candidate has inadvertently increased his height by 5/4  the correction he would need to make to go back to his original height would be to reduce the stated height by 1/5 which is 20% .

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In a mixture of 100 l l of milk and water, 25% of mixture is milk. How much water should be added to mixture so that milk become 20% of mixture?

Hi Nancy ,

Quantity of milk in the mixture = 25 litres

Quantity of water in the mixture = 75 litres

Let x litres of water be added in the mixture so that [25/ ( 100 + x) ] × 100 = 20

x = 25

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A watermelon contains 85% of water. 30 g of water evaporates from watermelon and now it containsb80%water. What was original weight of watermelon?

Hi Nancy ,

Let the original weight of the watermelon be x gm.

Water : 85 % of x

Solid Pulp : 15 % of x

30 g water evaporates so ,

New weight : (x - 30 )gm

Water : 80 %  of ( x - 30) gm

Solid Pulp : 20 % of ( x - 30)

Now , 15 % of x   = 20 % of ( x - 30)

x = 120 gm

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In a college, 65% of students pass their exam in first year. Among tha students who have to repeat the exam in second year, 50% pass on their second attempt. Among the students who have to retake the paper the third time, 70% pass on their third attempt. What % of students had to take the exam more than 3 times

Hi Nancy!

Let the number of students be x .

65 % pass the exam in their first attempt, so 35% re-take the exam in the 2nd year i.e = 35x/100 = 7x/20

50 % of 7x/20 pass the exam on their 2nd attempt i.e = 7x/40, so 7x/20 take the exam.

70% of 7x/40 pass the exam on their third attempt, so 30 % of 7x /40 take the exam more than 3 times.

30% of 7x/40= [100(21x/400)/x] %= 5.25 % students had to take the exam more than 3 times.

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After two successive increase, the orice of a property has become 15/8 times the initial value. By how much percent oice was increased for the first timeif second increase was twice as high as first?

Hi Nancy!

(1+x)(1+2x)= 15/8

=> 2x² + 3x - 7/8 = 0

=>16x² + 24x - 7 = 0

=>x= 1/4= 25%

in an exam, 48% students failed in phy, 32% students in chem, 20% students failed in both the subjects. If no of students who passed in both was 880, how many students appeared in exam?

100 - (28 + 20 + 12) = 40%  passed the exam

40% of Total students = 880

100% = 2200

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