The graph below shows the average rating given by 20 critics to six different restaurants in three different parameters Ambience, Food & Service. The maximum rating to any restaurant in any parameter by a critic can be 100.

Q.1 Number of Critics who gave a rating of less than 40 to all restaurants in Ambience cannot be more than

The maximum average of rating in Ambience is 96 for Moonshine café. Hence the total rating by the 20 critics will be 96×20 = 1920. Suppose 2 critics rated 39 and the rest 18 rated 100 then the total sum would be 1800+39×2 = 1878. So the required number of critics would be less than 2. We can see that if 19 were to give the rating of 100 there would be 1 who will give a rating of 20.

Hence the maximum number of required critics can be 1.

Option B is correct.

Q.2 If no critic rated less than 40 to any of the restaurants in Food, at most how many critics could have given a rating of exactly 100 to atleast 1 restaurant in Food?

The average rating in Food for Social is maximum at 93. Hence the total rating by 20 critics would be 93×20 = 1860. Here we can have 17 critics who could have rated 100 and the rest 3 could have rated 50,50 & 60 which satisfies our condition. Similarly the other 3 critics can give a rating of 100 to Moonshine Café. So, all 20 critics can give a rating of 100 to atleast 1 restaurant in Food.

Option D is correct.

Q.3 The number of critics who gave a rating of more than 90 to all restaurants in each of the three parameters could not be more than

The minimum average rating in any parameter is of Social in Ambience which is 65. So its total rating will be 65×20 = 1300. If the critics were to give 91 rating, then the number of critics who can give 91 rating will be at most [1300/91] = 14 (where [x] represents Greatest Integer Less than or equal to x).

Option B is correct.

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