**Solution:**

**This is based on utilization of maximum efficiency**

**point where 800 carrots can be transported using 2.5 return trips, means in 5 one side trips.**

** To reach to this point horse will eat 400 carrots in 5 triops. means this point is 80 miles away. **

**Now the remaining distance is 320 miles**

**Next the point where 400 carrots can be transported in 1.5 round trips or 3 one side trips. **

**horse will eat 400 carrots to get there in 3 trips, means 133 miles away. **

**now the remaining distance is 320-133= 187 miles and carrots are 401 left. so now horse will further eat 187 carrots.**

**So the maximum carrots transported will be 401-187 = 214 carrots**

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