Collection of Coins 

0.01 + 0.02 + 0.05 + 0.10 + 0.20 + 0.50 + 1 + 2 = 3.88 ( value in rupees)

1+2+5+10+20+50+100+200 = 388  (value is paise)
So, Total amount is 388x = 100I+y, where I is an integer and y is one of the coin in paise

=> y = 388x-100I

=> y = 4(97x-25I)

hence y should be a multiple of 4

Clearly y can not be 1, 2 , 5 , 10 , 50 

For y = 20, minimum x will be 15
For y = 100 and 200, minimum x will be 25

So, total amount = 388 × 15 = 5820, after removing 20 paise

remaining value 5800 paise = 58 rupees