Puzzle Of The Day: 90
A 5-member cricket team has to be selected for a new format of cricket named Hong Kong Super Five! It must be composed of 2 batswomen, 2 bowlers and one wicket-keeper.There are three batting contenders viz. Supriya, Sumaya and Sanjana. There are two wicket-keeping contenders viz. Sunita and Sarita. There are three bowling contenders viz. Savita, Sujata and Suprita. If Savita is selected in the team, then Suprita cannot be selected. If Sanjana is selected, then Savita cannot be selected. If Sumaya is selected, then Sanjana also has to be selected.
Which of the following is the list of four players who can be selected together if Sunita is already selected?
1.Supriya, Sumaya, Savita and Sujata
2. Sumaya, Sanjana, Sujata and Savita
3. Supriya, Sanjana, Sujata and Suprita
4. Supriya Sanjana, Sarita and Suprita
We need 2 batswomen, 2 bowlers and 1 wicket keeper. There are 3 batswomen, namely Supriya, Sumaya and Sanjana. If Sumaya is selected, Sanjana has to be selected. If Sumaya is not selected, the batters will be Supriya and Sanjana. Therefore, Sanjana must be selected to the team. Moreover, if Sanjana is selected, Savita cannot be selected. Therefore, we have to select from the following: Batswomen: Sanjana and Supriya/Sumaya Bowlers: Sujata and Suprita
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