Numbers
Given below is the sequence of all the natural numbers which don’t contain the digit ‘0’.
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13…
What is the product of the digits of 200th term of this sequence?
1. 12
2. 8
3. 6
4. 21
Inthe first 200 natural numbers there are 20 numbers whose unit digit is ‘0’,there are 11 numbers whose tens digit is ‘0’ and there are 2 natural numbers which have both the unit and the tens digit as ‘0’. So in all there are 200 –(20 + 11 – 2) = 171 such numbers which do not have ‘0’ as any digit. The 172nd,181st, 190th and 199th term of the given sequence will be 211, 221, 231 and 241 respectively. So the 200th term will be 242.
Product of the digits of 242 : 2 x 4 x 2 = 12
See our previous ‘Questions of the Day’:
https://tathagat.mba/quant-question-of-the-day-130/
https://tathagat.mba/quant-question-of-the-day-129/
0 comments