Quant Question Of The Day: 135
If x2+ y2 = 14x – 6y – 58, then what is the maximum value of 3x + 2y ? x2
+ y2 = 14x – 6y – 58 Or (x-7)2
+ (y+3)2 = 0 Since
(x-7)2 and (y+3)2 is always positive so the only value of
x and y that satisfy the above
equation is x = 7 and y =-3 So, the maximum value of 3x+ 2y = 15
1. -12
2. 15
3. 10
4. 6
5. None of these
See our previous ‘Questions of the Day’:
https://tathagat.mba/quant-question-of-the-day-134/
https://tathagat.mba/quant-question-of-the-day-133/
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