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Find the sum of all four-digit numbers N whose sum of digits is equal to 2010 – N.
Find the sum of all four-digit numbers N whose sum of digits is equal to 2010 – N.
N has to be greater than 2010 – 28 = 1982 because maximum sum of digits less than 2010 is 1 + 9 + 9 + 9 i.e. 28. Now checking for all the decades there are only two possible values of N i.e. 1986 and 2004. So the required sum is 3990.
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By Những dòng bồn cầu thông minh ... , 1 month ago
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