Quant Question Of The Day : 1

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Geometry

In the figure, ABCD is a rhombus. Point E is on the diagonal AC such that AE = 41, EC = 9 and measure of ∠ABE = 90º. Find the area of this rhombus.

 

 

 

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7 comments

    1. Raman Sharma

      Hello , Karan !

      no,BO² = AO × OE is correct.

      Triangle AOB and triangle BOE are similar triangles .

      => AO/BO = BO/OE

      Hence , BO² = AO × OE

      ( It is true for every Right Angled Triangle , the perpendicular drawn from the vertex of a right angled triangle to its hypotenuse is geometric mean of the two parts of that it divides the hypotenuse into. )

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