Quant Question Of The Day: 164
Algebra – Geometry
The perimeter of an equilateral triangle exceeds the perimeter of a square by 1989 cm. The length of each side of the triangle exceeds the length of each side of the square by d cm. The square has perimeter greater than zero. How many positive integers are not possible values for d?
If ‘t’ is the side of the triangle and ‘s’ is the side of the square, then Solving the first equation for t gives
3t – 4s = 1989
t – s = d
t = (4s + 1989)/3
(4s + 1989)/3 – s = d
s + 1989 = 3d
if s = 0, d = 663
but s has to be greater than 0. So, the first 663 integers are not possible.
See our previous ‘Questions of the Day’:
Quant Question Of The Day: 163
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