Quant Question Of The Day: 167
Geometry
A three-dimensional rectangular box with dimensions X, Y and Z has faces whose surface areas are 24, 24, 48, 48, 72, and 72 square units. What is X + Y + Z?
A three-dimensional rectangular box with dimensions X, Y and Z has faces whose surface areas are 24, 24, 48, 48, 72, and 72 square units. What is X + Y + Z?
Answer : 22
Solution :
XY = 24……(i)
YZ = 72….(ii)
XZ = 48….(iii)
(ii)/(i) = YZ/XY = 3 => Z/X = 3….(iv)
now (iv)*(iii) gives us Z2 = 144 => Z = 12
Following X = 4 and Y = 6.
X + Y + Z = 12 + 6 + 4 = 22.
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