Quant Question Of The Day: 181
Numbers
There are 10 consecutive positive integers written on a blackboard. One number is erased. The sum of remaining nine integers is 2011. Which number was erased?
There are 10 consecutive positive integers written on a blackboard. One number is erased. The sum of remaining nine integers is 2011. Which number was erased?
Sum of remaining 9 numbers = 9n + 45 – k = 2011 9n = 1966+K for RHS to be a multiple of 9, value of K= 5 n = 219 Hence the missing number is 224.
Let’s say 10 numbers are n, n + 1,….. and n + 9 and missing number is n + k .
Sum of these 10 numbers = 10n + 45
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good information
By Những dòng bồn cầu thông minh ... , 1 month ago
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