Quant Question Of The Day: 188
Algebra
If x and y are real numbers, find the number of solutions of the equation x2 + 2y2 – 2xy – 2x + 2 = 0
1. No solution
2. One solution
3. Two solutions
4. Four solutions
If x and y are real numbers, find the number of solutions of the equation x2 + 2y2 – 2xy – 2x + 2 = 0
1. No solution
2. One solution
3. Two solutions
4. Four solutions
x2 + 2y2 -2xy -2x + 2 = 0
2x2 + 4y2 – 4xy – 4x + 4 = 0
x2 + 4y2 – 4xy + x2 + 4 – 4x = 0
( x – 2y)2 + ( x-2)2 = 0
x = 2 , y = 1
Hence , one solution.
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