Quant Question Of The Day: 201
Find a + b + c + d + e if
6a + 4b + 8d = 20,
a + b + 2c + 5e = 3
3a + 6b + 9c +3d = 21
Find a + b + c + d + e if
6a + 4b + 8d = 20,
a + b + 2c + 5e = 3
3a + 6b + 9c +3d = 21
from 1st 3a+2b+4d = 10 ……..(4) and 2nd a+b+2c+5e = 3……..(5) from 3rd a+2b+3c+d = 7…….. (6) now add (4), (5), (6) 5a + 5b + 5c + 5d + 5e = 20 Hence, a + b + c + d + e = 4.
Adding the first , third and fifth equations we get ,
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