Quant Question Of The Day: 205
How many of the ordered pairs of positive integers (A,B) satisfy the equation: A + B + AB = 111 ?
How many of the ordered pairs of positive integers (A,B) satisfy the equation: A + B + AB = 111 ? i.e. 1 + A+ B + AB = (A + 1)(B + 1) = 3*37 As A, B are positive integers, both the terms (A+ 1) and (B+ 1) are greater than or equal to 2. Also they are factors of 111.
A+B+AB = 111
So required number of ordered pairs of positive integers (A, B) = (number of positive integral divisors of 11) – 2 = 4-2 = 2 .
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