Quant Question Of The Day: 222
Last 2 digits of N are 38 and there are 3 factors between root(N) and 1. Then what is the number of factors of N.
- 9
- 8
- 6
- either (1) or (2)
Last 2 digits of N are 38 and there are 3 factors between root(N) and 1. Then what is the number of factors of N.
Ans: (2) 8 Solutions 3 factors between 1 and root(N), hence 4 are less than root(N) so 4 are greater than N. and N is not a perfect square because last digit cannot be 8 for a perfect square. Hence total There 8 factors for N.
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good information
By Những dòng bồn cầu thông minh ... , 1 month ago
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