[latexpage]
ABCDEF is an equiangular hexagon ( each of its interior angle is 120°) . Find the EF + FA, if AB = 2, BC = 4, CD = 3 and DE = 5.
A. 4
B. 5
C. 6
D. 7
E. None of these
Because ∠ABC = 120°, so ∠CBR = 60°, similarly ∠BCR = 60°. Thus ∠R = 60°.
Similarly ∠P = ∠Q = 60°.
So PR = 5 + 3 + 4 = 12, and PQ = 5 + EF + FA = 12.
Hence EF + FA = 12 – 5 = 7.
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A.
Hi Shivam
7 is the correct answer . Check the solution here : http://tathagat.mba/quant-question-of-the-day-23/
Do try today’s question : http://tathagat.mba/quant-question-of-the-day-24/
None of the above
Hello Aaradhya!
Option D is correct . Check the solution here : http://tathagat.mba/quant-question-of-the-day-23/
Do try today’s question : http://tathagat.mba/quant-question-of-the-day-24/