Quant Question Of The Day: 267
Geometry
The angle bisectors BD and CE of a triangle ABC are divided by the incentre I in the ratios 3 : 2 and 2 : 1 respectively. Then the ratio in which I divides the angle bisector through A is-
(A) 3 : 1
(B) 11 : 4
(C) 6 : 5
(D) 7 : 4
See our previous ‘Questions of the Day’:
Quant Question Of The Day: 266
Quant Question Of The Day: 265
Quant Question Of The Day: 264
3:1
11:4
11:4
11:4