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Algebra

 

Find a + b + c + d + e if

3a + 2b + 4d = 10,
6a + 5b + 4c + 3d + 2e = 8,
a + b + 2c + 5e = 3,
2c + 3d + 3e = 4, and
a + 2b + 3c + d = 7.

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11 comments

  1. Shrey Rawal

    3a + 2b + 4d+a + b + 2c + 5e+a + 2b + 3c + d=
    5a+5b+5c+5d+5e=20
    Div by 5
    a+b+c+d+e= 4

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