Quant Question Of The Day: 40
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Geometry
In the given figure ,Angle ABC = 90º F is the center of the semicircle . AE = 6 cm and AB = 12 cm . Find the length of BC .
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EC = BC = x
AC*2 = BC*2 + AB*2
(ANGLE FBC = 90° BECAUSE RADIUS ALWAYS MAKES 90° ANGLE WITH TANGENT )
BC = 9 cm
Perfect Piyush!
9
Correct!
9
AC=BC=a
(a+6)^2= a^2+12^2
Hence a=9
Well done Abhishek!
BC=9
Correct
Sir could you please provide its solution , my answer is still incorrect .