Quant Question Of The Day: 47
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How many of the ordered pairs of positive integers (T, G) satisfy the equation: T + G + TG = 2018 ?
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How many of the ordered pairs of positive integers (T, G) satisfy the equation: T + G + TG = 2018 ?
i.e. 1 + T + G + TG = (T + 1)(G + 1) = 2019 = 3×673.
As T, G are positive integers, both the terms (T + 1) and (G + 1) are greater than or equal to 2. Also they are factors of 2019.
So required number of ordered pairs of positive integers (T, G) = (number of positive integral divisors of 2019) – 2 = 4-2 = 2 .
New Question: Coordinate Geometry
good information
By Những dòng bồn cầu thông minh ... , 1 month ago
No. Of factors of 2018
1,2,109,2018
But no ordered pair that makes 2018
According to me-0
Shouldn’t there be 2?
(2 , 672) and (672 , 2).
2 ordered pairs according to me. (2,672) and (672,2).