Quant Question Of The Day: 53
[latexpage]
Numbers
How many three digit numbers are increased by 99 when there digits are reversed ?
A. 4
B. 8
C. 10
D. 80
E. 90
See our previous ‘Questions of the Day’:
Recent Forum Posts/Questions/Answers
New Question: Coordinate Geometry
good information
By Những dòng bồn cầu thông minh ... , 6 months ago
Recent Blog Posts
Recent Blog Comments
- LouisHayes on Quant Question Of The Day: 275
- pankaj saket on GK Question of the day: 22
- sajal on Puzzle of The Day
- sajal on Puzzle of The Day
- Lalit Bansal on Quant Question Of The Day: 275
- Rajendra Kumar on Countdown to CAT 2020|DAY 87|LRDI
- Shruti Tiwari on GK Question of the day: 21
- Deepika on GK Question of the day: 21
- Deepika on Quant Question Of The Day: 275
- Anubhav Swaroop on Quant Question Of The Day: 269
Other websites
© 2007-2020 by TathaGat.
Ans. D=80
100a + 10b+c +99= 100c +10b+a
99a-99c = – 99
c-a =1
With this condition (a,c) will take values (1,2),(2,3),(3,4)….(8,9)
b can take any value from 0-9
Numbers will be 102,203,304……112,213……122,223…….192,293,394…899.
Answer :D=80
100a+10b+c+99= 100c+10b+a
99a-99c+99=0
c-a=1
Values for (a,c) will be (1,2),(2,3)..(8,9)
b can take any value from 0-9
D. 80
90
D. 80
80