Quant Question Of The Day: 98
Algebra
How many real numbers x are solutions to the following equation ?
|x − 1| = |x − 2| + |x − 3|
How many real numbers x are solutions to the following equation ?
|x − 1| = |x − 2| + |x − 3|
If x < 1, the equation becomes (1 – x) = (2 – x) + (3 – x) which simplifies to x = 4, contradicting the assumption the assumption x < 1. If 1 < x < 2, we get (x – 1) = (2 – x) + (3 – x), which gives x = 2. If 2 ≤ x ≤ 3, we get (x – 1) = (x – 2) + (3 – x), which again gives x = 2. If x ≥ 3, we get (x – 1) = (x – 2) + (x – 3), or x = 4. So 2 and 4 are the only solutions, and the answer is 2.
New Question: Coordinate Geometry
good information
By Những dòng bồn cầu thông minh ... , 1 month ago
2 values of x
X= 2 and 4
x=2&4
2