Sol.  b)

Since the overall percentage of gold coins in the loot is 40% and for both Shamu and Gopi the gold coins account for 60% of their share of coins, thus we can deduce that x<40% (for the average of the gold coin tally to be 40%).

Similarly, overall percentage of silver coins in the loot is 60% and for both Shamu and Gopi the silver coins account for 40% of their share of coins, thus we can deduce that y>60%.

Hence x<y

Sol. b)

All coins with Ramu would be categorized in one of the two categories, gold or silver, thus x+y = 100

So the expression 3y + 2x = 3(x+y) –x = 300-x

Now, if Total number of coins with Ramu is 800, the coins with Shamu and Gopi combined is 1200.

60% of coins with Shamu and Gopi are Gold coins, thus Ramu’s share of gold coins becomes (2000*2/5) – (.6*1200) which is also equal to x% of 400

Or x*800/100=800-720

Or x = 10%

And the value of expression 3y + 2x = 3(x+y) –x = 300-x = 300-20 =290

Sol. a)

Refer to the table below

The final ration 6:9:5 is equal to 18:27:15